3x^2-5x=16

Solution for 3x^2-5x=16 equation:

3x^2-5x=16

We move all terms to the left:

3x^2-5x-(16)=0

a = 3; b = -5; c = -16;
Δ = b2-4ac
Δ = -52-4·3·(-16)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{217}}{2*3}=\frac{5-\sqrt{217}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{217}}{2*3}=\frac{5+\sqrt{217}}{6}
$